Since all blue 3, 4, and 5 are all 3-segment waves, I would call them wave-C, D, E (to distinquish them from regular 5-segment waves). Same as all those red 1, 2, 3, 4, so I would call the red ones A, B, C, D, ... E.
Since red waves are all in 3-segment fashion, we could expect the black 3 as the final killing ... if this bearish count is valid. Why? See ... we have red 1 2 3 4 already (in my term A, B, C, D), so the bear is waiting for a red-5 (wave-E in my term). Right?! OK, since all red fractals are in 3-segment fashion, and since we have black 1 and 2 which serve as the first 2 segments of the red-5, the black-3 will be the third segment of the red-5.
Continue on ... if the bearish count is valid, we will expect the final killing (black 3). The only question is how deep the final slaughtering will be? We have seen a big extension in the wave-3 (wave-C in my term) from 135 to 111. In normal case, the extension occurs only once, which means that the final killing won't be too deep. Of course in some exteme case, two extensions happen inside a big fractal, which means the final killing could reproduce the extension to a very deep level.作者: snowrider 时间: 2011-9-10 00:29
图片附件: spy.png (2011-9-9 23:47, 35.46 KB) / 下载次数 8
